Roman to Integer Interview question asked by Top Companies

Suppose we have Roman literals; we have to convert them into an integer. As we know the Roman numerals represent in some different symbols as below:

For example, 2 is written as II in Roman numeral, just two ones added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

• I can be placed before V (5) and X (10) to make 4 and 9. 
• can be placed before L (50) and C (100) to make 40 and 90. 
• C can be placed before D (500) and M (1000) to make 400 and 900.

Input: s = "III"
Output: 3
Explanation: III = 3.

Input: s = "LVIII"
Output: 58
Explanation: L = 50, V= 5, III = 3.

Input: s = "MCMXCIV"
Output: 1994
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

Constraints:

• 1 <= s.length <= 15
• s contains only the characters ('I', 'V', 'X', 'L', 'C', 'D', 'M').
• It is guaranteed that s is a valid roman numeral in the range [1, 3999].

Solution in python3

class Solution:
    romman_to_number = {
        "I": 1,
        "V": 5,
        "X": 10,
        "L": 50,
        "C": 100,
        "D": 500,
        "M": 1000
    }

    def romanToInt(self, s: str) -> int:
        total = 0
        for i in range(len(s)):
            if i+1 < len(s) and self.romman_to_number[s[i]] < self.romman_to_number[s[i+1]]:
                total -= self.romman_to_number[s[i]]
            else:
                total += self.romman_to_number[s[i]]
            
        return total